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These are the user uploaded subtitles that are being translated: 1 00:00:03,000 --> 00:00:03,930 Instructor: Hello again. 2 00:00:03,930 --> 00:00:05,550 This is going to be a short lecture 3 00:00:05,550 --> 00:00:08,283 where we focus on the symmetry of combinations. 4 00:00:09,150 --> 00:00:11,850 Unlike permutations and variations, 5 00:00:11,850 --> 00:00:15,870 picking more elements can lead to having fewer combinations. 6 00:00:15,870 --> 00:00:17,580 Imagine you are going on a picnic 7 00:00:17,580 --> 00:00:20,940 and have six pieces of fruit you want to take with you. 8 00:00:20,940 --> 00:00:24,510 However, your basket only has room for four of them. 9 00:00:24,510 --> 00:00:26,190 Using the combinations formula, 10 00:00:26,190 --> 00:00:29,610 we are going to have 15 possible choices. 11 00:00:29,610 --> 00:00:32,670 Therefore, you go out and buy a bigger basket, 12 00:00:32,670 --> 00:00:36,480 but it turns out it can only fit five pieces of fruit. 13 00:00:36,480 --> 00:00:39,390 According to the formula, there are just six ways 14 00:00:39,390 --> 00:00:41,163 of picking the five fruits. 15 00:00:42,000 --> 00:00:43,920 What if you get an even bigger basket 16 00:00:43,920 --> 00:00:46,110 which can fit six fruits? 17 00:00:46,110 --> 00:00:48,390 Well, in how many ways can you pick 18 00:00:48,390 --> 00:00:51,300 six fruits out of six fruits? 19 00:00:51,300 --> 00:00:53,940 Only one, picking all of them. 20 00:00:53,940 --> 00:00:57,450 So we see that, in this case, picking more elements 21 00:00:57,450 --> 00:00:59,613 leads to having fewer combinations. 22 00:01:00,600 --> 00:01:02,640 This is because we can construct the question 23 00:01:02,640 --> 00:01:03,590 in a different way. 24 00:01:04,560 --> 00:01:07,080 Instead of picking which pieces of fruit to take, 25 00:01:07,080 --> 00:01:09,930 we can choose the pieces to leave behind. 26 00:01:09,930 --> 00:01:12,480 Therefore, picking four fruits out of six 27 00:01:12,480 --> 00:01:16,470 is the same as choosing two fruits that will be left out. 28 00:01:16,470 --> 00:01:19,950 Mathematically, selecting two elements out of six 29 00:01:19,950 --> 00:01:23,520 equals six factorial over two factorial 30 00:01:23,520 --> 00:01:26,043 times four factorial, or 15. 31 00:01:26,910 --> 00:01:29,640 How about five out of six fruits? 32 00:01:29,640 --> 00:01:31,440 It's the same as choosing which one 33 00:01:31,440 --> 00:01:33,600 out of the six to leave behind. 34 00:01:33,600 --> 00:01:36,540 In the general case, we can pick P many elements 35 00:01:36,540 --> 00:01:40,830 in as many ways as we can pick N minus P many elements. 36 00:01:40,830 --> 00:01:43,650 This shows us that when it comes to combinations, 37 00:01:43,650 --> 00:01:45,090 the number of possible ways 38 00:01:45,090 --> 00:01:49,080 in which P many elements can be selected is symmetric 39 00:01:49,080 --> 00:01:51,900 with respect to n over 2 40 00:01:51,900 --> 00:01:54,423 And this symmetry is the topic of this lesson. 41 00:01:55,740 --> 00:01:56,943 So far, so good. 42 00:01:57,840 --> 00:01:59,880 Recall the example where we had to select 43 00:01:59,880 --> 00:02:02,970 3 of our 10 employees to represent the company 44 00:02:02,970 --> 00:02:03,903 at a conference. 45 00:02:05,130 --> 00:02:09,479 As we already showed, there are 120 possible selections. 46 00:02:09,479 --> 00:02:11,280 What if instead of choosing three, 47 00:02:11,280 --> 00:02:14,610 we had to pick seven people to go to the conference? 48 00:02:14,610 --> 00:02:17,190 While using the formula we defined in the last lecture, 49 00:02:17,190 --> 00:02:20,706 the number of combinations we would have is 10 factorial 50 00:02:20,706 --> 00:02:25,110 over 7 factorial times 3 factorial. 51 00:02:25,110 --> 00:02:29,130 That's equivalent to 8 times 9 times 10 52 00:02:29,130 --> 00:02:32,640 over 1 times 2 times 3, 53 00:02:32,640 --> 00:02:35,760 or 720 divided by 6 54 00:02:35,760 --> 00:02:37,713 which is 120. 55 00:02:38,580 --> 00:02:41,850 Thus, we would also have 120 different ways 56 00:02:41,850 --> 00:02:43,443 of picking the seven employees. 57 00:02:44,880 --> 00:02:47,430 That's because picking 7 out of 10 employees 58 00:02:47,430 --> 00:02:48,750 to take to the conference 59 00:02:48,750 --> 00:02:51,933 is the same as choosing 3 out of 10 to leave behind. 60 00:02:53,580 --> 00:02:57,000 Great. Please go ahead and check the additional resources 61 00:02:57,000 --> 00:03:00,930 for this course to see how we prove symmetry mathematically. 62 00:03:00,930 --> 00:03:02,070 I believe this would reinforce 63 00:03:02,070 --> 00:03:03,670 your understanding of the topic. 64 00:03:05,940 --> 00:03:06,930 All right. 65 00:03:06,930 --> 00:03:09,993 To sum up, when P is greater than n over 2, 66 00:03:10,950 --> 00:03:13,590 n minus p would be smaller than p. 67 00:03:13,590 --> 00:03:16,290 In such instances, we could apply symmetry 68 00:03:16,290 --> 00:03:19,830 to avoid calculating factorials of large numbers. 69 00:03:19,830 --> 00:03:22,890 Generally, we use symmetry to simplify the calculations 70 00:03:22,890 --> 00:03:23,763 we need to make. 71 00:03:24,840 --> 00:03:25,923 Thanks for watching. 5504

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