Afrikaans
Akan
Albanian
Amharic
Arabic
Armenian
Azerbaijani
Basque
Belarusian
Bemba
Bengali
Bihari
Bosnian
Breton
Bulgarian
Cambodian
Catalan
Cebuano
Cherokee
Chichewa
Chinese (Simplified)
Chinese (Traditional)
Corsican
Croatian
Czech
Danish
Dutch
English
Esperanto
Estonian
Ewe
Faroese
Filipino
Finnish
French
Frisian
Ga
Galician
Georgian
German
Greek
Guarani
Gujarati
Haitian Creole
Hausa
Hawaiian
Hebrew
Hindi
Hmong
Hungarian
Icelandic
Igbo
Indonesian
Interlingua
Irish
Italian
Japanese
Javanese
Kannada
Kazakh
Kinyarwanda
Kirundi
Kongo
Korean
Krio (Sierra Leone)
Kurdish
Kurdish (Soranรฎ)
Kyrgyz
Laothian
Latin
Latvian
Lingala
Lithuanian
Lozi
Luganda
Luo
Luxembourgish
Macedonian
Malagasy
Malay
Malayalam
Maltese
Maori
Marathi
Mauritian Creole
Moldavian
Mongolian
Myanmar (Burmese)
Montenegrin
Nepali
Nigerian Pidgin
Northern Sotho
Norwegian
Norwegian (Nynorsk)
Occitan
Oriya
Oromo
Pashto
Polish
Portuguese (Brazil)
Portuguese (Portugal)
Punjabi
Quechua
Romanian
Romansh
Runyakitara
Russian
Samoan
Scots Gaelic
Serbian
Serbo-Croatian
Sesotho
Setswana
Seychellois Creole
Shona
Sindhi
Sinhalese
Slovak
Slovenian
Somali
Spanish
Spanish (Latin American)
Sundanese
Swahili
Swedish
Tajik
Tamil
Tatar
Telugu
Thai
Tigrinya
Tonga
Tshiluba
Tumbuka
Turkish
Turkmen
Twi
Uighur
Ukrainian
Urdu
Uzbek
Vietnamese
Welsh
Wolof
Xhosa
Yiddish
Yoruba
Zulu
1
Everyone in this video were briefly going to talk about what's called initial value problems so initial
2
value problems.
3
I just wanna explain the concept behind them and what they mean.
4
So high.
5
V.P. is an easy way to abbreviate initial value problem.
6
Due to examples.
7
So Example 1 say we have a differential equation so d y the X and it's equal to some stuff over here
8
on the right hand side with Xs and Ys so to indicate that I'm gonna to write F of X comma Y.
9
So all this means is that we have some stuff with X's and Y's that's all that notation means.
10
Okay.
11
So like X plus Y etc. X squared plus sine Y etc. I just stop with X and Y then we have a condition Y
12
of x sub zero equals Y some zero.
13
This is called an initial condition.
14
So initial condition and typically I like to revisit it as I see.
15
So that's our I see s our initial condition.
16
So what does this mean graphically.
17
Well if you solve a differential equation you know most of the time you get like you know X squared
18
plus C or something like that you get a constant.
19
In this case you would get one arbitrary constant so you might get like you know infinitely many solutions
20
so something like this.
21
And then something like this something like this one for each choice of C right you have infinitely
22
many solutions.
23
And so what's happening here is that this initial condition well what does this mean.
24
This means that the x coordinate is X not on the y coordinate is why not.
25
So this means that your solution passes this point.
26
So what it's doing is it's picking a particulates solution from the infinitely many solutions.
27
So like maybe it's picking this one.
28
So this red graph here this this would be the solution
29
to the AVP
30
so whenever you have one arbitrary constant and your solution you haven't wanted whenever you have a
31
one parameter family to find a particular solution you would need one initial condition.
32
In this case the initial condition tells us graphically that our solution passes the point.
33
So we have infinitely many solutions and then we're picking a particular one.
34
Right.
35
Maybe that's what the name particular comes from right.
36
Because once you use this you're gonna find your C so you'll get something like Y equals.
37
Making this up but X squared plus four let's say.
38
So that might be your answer.
39
So this is called a particular solution because it has no C's.
40
So that's that's an initial value problem.
41
Here's another example.
42
Say we had DIY D X equal to now actually mean do a second derivative here.
43
There we go.
44
Equal to some stuff with X Y and the first derivative.
45
So now we have an order to differential equation so X Y and then the first derivative.
46
So this is just some stuff with X Y and the first derivative.
47
So now we need to initial conditions maybe y of x sub zero equals Y sub zero and then Y prime of x sub
48
zero equals Y sub one equals Y sub 1.
49
So now again say we have you know infinitely many solutions you know something like this
50
right.
51
And then what this does is it obviously it picks the one that passes through through X not why not.
52
So it picks that one.
53
So maybe that would be this one here so it would pick that one but not only that it guarantees that
54
the slope at this point is is this right this slope slope is why 1 the slope of this tangent line is
55
why once the slope of the function or the tangent line at that point is equal to that.
56
So this requires two things.
57
Right.
58
It passes through this point and it has this particular slope at that point.
59
So in this case if like if you were to solve this d e maybe it would be something like I'm just gonna
60
make this up.
61
C 1 each of the X plus C 2 x squared was totally making this up.
62
So you'd have to seize and see what you would have to use both of these conditions to find both CS and
63
when you do that you would get the particular solution.
64
So in this case the particular solution would be would be that right there.
65
So I hope that made sense.
66
I'm going to make another video showing you a little bit more how to how to actually find the seas and
67
stuff like that.
68
That's it.
Can't find what you're looking for?
Get subtitles in any language from opensubtitles.com, and translate them here.