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These are the user uploaded subtitles that are being translated: 1 00:00:01,320 --> 00:00:02,969 We can also sort alphabetically. 2 00:00:05,130 --> 00:00:08,250 The goal of this lesson is to sort by class name and price. 3 00:00:10,120 --> 00:00:13,750 Open up the folder for this lesson by following this path inside the resources. 4 00:00:19,260 --> 00:00:21,720 The string class also implements comparable. 5 00:00:24,150 --> 00:00:27,420 It follows that the string class overrides compared to. 6 00:00:29,310 --> 00:00:35,130 The compared to method for string objects returns a negative number if the character in the first string 7 00:00:35,130 --> 00:00:38,880 has a lower Unicode value than the character in the specified object. 8 00:00:41,500 --> 00:00:44,440 Zero, if the strings are identical, which makes sense. 9 00:00:46,340 --> 00:00:51,830 And a positive number, if a character in the first string has a higher Unicode value than a character 10 00:00:51,830 --> 00:00:52,880 in the second string. 11 00:00:55,430 --> 00:01:00,350 We'll test the first case first, we have John and Amy, we'll call Amy compared to. 12 00:01:02,110 --> 00:01:02,650 John. 13 00:01:05,010 --> 00:01:09,150 The letter A. is expected to have a lower Unicode value than the letter J. 14 00:01:09,480 --> 00:01:11,340 So that's going to return a negative number. 15 00:01:12,780 --> 00:01:13,390 Perfect. 16 00:01:13,860 --> 00:01:15,630 Now, I'll compare Amy to Amy. 17 00:01:21,950 --> 00:01:23,870 Returns zero expected. 18 00:01:25,250 --> 00:01:27,440 Now, I'm going to compare John against Jane. 19 00:01:39,960 --> 00:01:47,550 JNJ, same Unicode value, but the letter O comes after a so we can expect a higher Unicode value perfect. 20 00:01:49,290 --> 00:01:51,570 And if we reverse it, we get a negative number. 21 00:01:56,060 --> 00:02:00,920 So based on this information that you just got, go back to the product application. 22 00:02:02,700 --> 00:02:08,789 And what I want you to do is sort the products by alphabetical order based on their class type, then 23 00:02:08,789 --> 00:02:10,320 sort the rest by price. 24 00:02:11,690 --> 00:02:17,270 Here are some hints you can get the class type by using get class and you can get the name of the class 25 00:02:17,270 --> 00:02:19,690 by using get class, get simple name. 26 00:02:20,450 --> 00:02:23,090 I'll give you the chance to pause the video and try this out. 27 00:02:27,910 --> 00:02:29,270 I hope you figured it out. 28 00:02:29,290 --> 00:02:33,850 So what I'm going to do is inside compared to I'll get the name of the current object. 29 00:02:35,090 --> 00:02:36,200 String class name. 30 00:02:39,030 --> 00:02:41,970 Is equal to this doGet class, that simple name. 31 00:02:43,190 --> 00:02:45,980 And I'll get the last name of the specified object. 32 00:02:58,880 --> 00:03:02,360 All right, now we're going to check if the class names aren't equal. 33 00:03:07,990 --> 00:03:12,820 If that's the case, we're going to return the result from comparing the first class name to the second 34 00:03:12,820 --> 00:03:13,090 one. 35 00:03:22,820 --> 00:03:28,820 Here we're comparing two strings, and if the two objects don't happen to share the same class, so, 36 00:03:28,820 --> 00:03:34,310 for example, if this is pants and this is shirt compared to is going to return an integer, that depends 37 00:03:34,310 --> 00:03:35,750 on the letters in each name. 38 00:03:38,220 --> 00:03:40,170 Let's test this out by running the debugger. 39 00:04:06,060 --> 00:04:08,790 These two objects don't share the same class. 40 00:04:09,060 --> 00:04:15,870 This is Pence, this is Schertz, the letter s is expected to have a higher Unicode value than the letter 41 00:04:15,870 --> 00:04:16,170 P. 42 00:04:16,589 --> 00:04:21,959 So this is going to return a positive value, which means shirt is going to come after pence. 43 00:04:41,600 --> 00:04:47,750 Now we're comparing pants and pants, the two pants are part of the same class, however, the price 44 00:04:47,750 --> 00:04:51,340 of the current object is higher than the price of the specified object. 45 00:04:51,650 --> 00:04:53,980 So compared to returns, a positive number. 46 00:04:54,140 --> 00:04:57,930 So it's going to sort the current object that come after the specified one. 47 00:04:58,250 --> 00:05:02,300 And so basically it's going to keep comparing each object against another object. 48 00:05:04,260 --> 00:05:06,960 First, it prioritizes alphabetical order. 49 00:05:08,800 --> 00:05:13,870 And if the two objects share the same class, then it's going to sort of by comparing the price of each 50 00:05:13,870 --> 00:05:14,470 product. 51 00:05:14,890 --> 00:05:20,050 Ultimately, we get an array where objects of different classes are sorted based on the class name, 52 00:05:20,410 --> 00:05:23,650 and every object of the same class are compared by price. 53 00:05:24,550 --> 00:05:31,000 The sort method can easily sort to comparable objects, sort uses compare to to determine how to sort 54 00:05:31,000 --> 00:05:31,720 your objects. 55 00:05:32,020 --> 00:05:37,660 And if the two objects don't have the same class, the one with characters that have a lower Unicode 56 00:05:37,660 --> 00:05:39,670 value are going to be sorted first. 57 00:05:40,030 --> 00:05:44,620 If the names happen to be equal, then the objects are compared based on their price. 58 00:05:45,010 --> 00:05:50,410 As a result, our comparable objects are sorted based on alphabetical order and price. 5741

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