All language subtitles for 7. Challenge 5 - Find the Next Date

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These are the user uploaded subtitles that are being translated: 1 00:00:00,200 --> 00:00:07,770 All right, so in this video, this amazing challenge, what we are going to do is to write a function 2 00:00:08,220 --> 00:00:16,410 that receives a date variable representing some given date, OK, based on our previous examples, very 3 00:00:16,410 --> 00:00:16,950 similar. 4 00:00:17,460 --> 00:00:24,130 And these functions should find and print the next day on the calendar. 5 00:00:24,630 --> 00:00:32,370 So if you're a date is something like 1st of October, 2001, let's say that's of a current date. 6 00:00:32,700 --> 00:00:44,640 Current date is simply like, I don't know, first of October, October 2001, then the printed result, 7 00:00:44,670 --> 00:00:53,840 the next date, the printed result should be should be something like 2nd of October, 2001. 8 00:00:54,210 --> 00:01:02,940 And while that's very simple, there are some cases that students find it hard to make this program 9 00:01:02,940 --> 00:01:04,380 and to answer this challenge. 10 00:01:04,890 --> 00:01:14,070 So my task to you guys, my request is before you move on and like view the whole solution that I'm 11 00:01:14,070 --> 00:01:21,870 giving to you, stop this video, take 20, 30 minutes, try try to write this program on your own. 12 00:01:22,170 --> 00:01:29,340 And once you are ready, once you are done, proceed with this video and make sure and see where you 13 00:01:29,340 --> 00:01:34,890 did one thing and I did another thing and trying to understand where is the difference. 14 00:01:35,310 --> 00:01:41,460 And if everything works correctly, then I think you are proceeding very well. 15 00:01:41,550 --> 00:01:49,350 And if not, make your notes, write your remarks and try on practicing even further. 16 00:01:49,380 --> 00:01:50,550 All right. 17 00:01:51,000 --> 00:01:51,830 Okay. 18 00:01:51,840 --> 00:01:53,220 And now I help. 19 00:01:53,220 --> 00:01:58,130 You are back and you are full of energy and you gave it a shot on your own. 20 00:01:58,380 --> 00:02:05,630 So what we want to do right now, I will still leave everything that I've created previously, the type 21 00:02:05,790 --> 00:02:11,820 struck date, as well as the print, the function, as well as the input date that is responsible for 22 00:02:11,820 --> 00:02:13,620 getting an input from the user. 23 00:02:14,100 --> 00:02:22,920 And what I'm going to use in the main function is simply, let's say, to create a new date. 24 00:02:23,040 --> 00:02:23,940 Simple as that. 25 00:02:24,270 --> 00:02:26,520 And what will be the type of this function? 26 00:02:26,540 --> 00:02:30,330 So first of all, let's say that the type of this function will be void. 27 00:02:30,600 --> 00:02:36,990 So void prefect's date, date DETI, for example, we're receiving a date variable. 28 00:02:37,770 --> 00:02:43,620 Now, what we have to do is to think about the logic behind the scenes as to how to find the next day. 29 00:02:43,800 --> 00:02:52,710 And it's and also taking into account that all of these days that all of these days may also come to 30 00:02:52,710 --> 00:02:57,390 this point thirty one, twelve months and the year and so on. 31 00:02:57,450 --> 00:03:05,490 OK, so the first thing that we have to do is to use something like that date day equals D.T., Dotti 32 00:03:05,910 --> 00:03:06,910 plus one. 33 00:03:06,960 --> 00:03:09,330 OK, we are incrementing just by one. 34 00:03:09,330 --> 00:03:13,650 So deti dot day plus plus would also work here. 35 00:03:13,680 --> 00:03:16,950 OK, and now we are going to ask a simple question. 36 00:03:18,210 --> 00:03:19,170 So awesome. 37 00:03:19,350 --> 00:03:23,100 I think that now we've managed to cover everything here. 38 00:03:23,220 --> 00:03:29,310 Also guys know that there are a lot of a couple actually of ways to solve this exercise. 39 00:03:29,340 --> 00:03:38,660 Also by taking into account the exact month of like month that have 30 days and months and months, 40 00:03:38,670 --> 00:03:40,500 that they have thirty one days. 41 00:03:40,680 --> 00:03:47,670 But the function itself simply will be a little bit longer and you will simply have to use now probably 42 00:03:47,670 --> 00:03:54,210 the best way will be to use switch cases and to like take January as having thirty one days and then 43 00:03:54,480 --> 00:03:58,170 taking the next month, thirty and so on, so forth. 44 00:03:58,170 --> 00:04:03,150 And you know, like taking into account that they are maybe once in four years. 45 00:04:03,150 --> 00:04:03,530 Right. 46 00:04:03,540 --> 00:04:07,110 Twenty eight and twenty nine days in February and so on. 47 00:04:07,560 --> 00:04:10,860 But that's not something that we are going to do right now. 48 00:04:11,160 --> 00:04:18,000 What we wanted just to see what kind of logic of how you find out and print the next day. 49 00:04:18,270 --> 00:04:27,870 And last thing do we have to add here is like something like that or print f the next day is OK and 50 00:04:27,870 --> 00:04:34,550 you simply print use the function print date to print our ADT, our outdated date. 51 00:04:34,560 --> 00:04:36,820 And there you go. 52 00:04:37,500 --> 00:04:40,770 So guys, run this program on your own. 53 00:04:41,160 --> 00:04:42,090 Take some notes. 54 00:04:42,240 --> 00:04:42,700 Right. 55 00:04:42,720 --> 00:04:47,220 And let me know if everything works for you correctly. 56 00:04:47,220 --> 00:04:55,050 If you have managed to make this exercise successfully on your own, if you found this information useful. 57 00:04:55,260 --> 00:04:59,580 And also what I wish you, as always, have a great day and. 58 00:04:59,680 --> 00:05:02,500 Keep on practicing, I'll see you next time. 5956

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