Would you like to inspect the original subtitles? These are the user uploaded subtitles that are being translated:
1
00:00:06,440 --> 00:00:15,650
In this network we've been told to subnet 1 9 2 1 6 8 2 1 0 slash 24 into 4 subnets.
2
00:00:15,670 --> 00:00:24,190
In other words we need a subnet for site one site to the serial link and this serial link.
3
00:00:24,190 --> 00:00:29,760
Now we haven't been told to use a slash of 30 mosque on the serial links.
4
00:00:29,770 --> 00:00:37,090
We'll do that in a separate video so all we need to do after this point is take 1 9 2 1 6 8 wondered
5
00:00:37,150 --> 00:00:42,460
0 slash 24 and subnet that into 4 subnets.
6
00:00:42,460 --> 00:00:49,750
Now when we look at a network address such as 1 9 2 1 6 8 1 0 we need to determine which point is the
7
00:00:49,750 --> 00:00:54,670
network and which part is the host portion.
8
00:00:54,670 --> 00:00:58,530
Currently this portion is the network portion.
9
00:00:59,560 --> 00:01:09,860
We can't change the network portion but we can manipulate and change the host portion of the address.
10
00:01:09,910 --> 00:01:15,500
So in other words what we can do is change this lost octet.
11
00:01:15,610 --> 00:01:23,320
The reason why we can't manipulate the first three octet is because that's part of the network 24.
12
00:01:23,320 --> 00:01:28,870
Essentially means that we have 24 binary ones.
13
00:01:28,870 --> 00:01:31,800
Now you don't have spaces in an octet like this.
14
00:01:31,810 --> 00:01:41,990
I'm just doing it to make it easier to read but essentially 24 means that we have 24 ones into the subnet
15
00:01:41,990 --> 00:01:55,300
mask so that's 24 binary ones which essentially equates to 255 255 255 is zero.
16
00:01:55,300 --> 00:02:02,590
It's important that you know how to convert a decimal to binary this binary value equates to decimal
17
00:02:02,740 --> 00:02:09,000
255 so the host portion of the address is once again that portion.
18
00:02:09,190 --> 00:02:16,030
This portion is the network portion we can't manipulate the network portion but to the host portion
19
00:02:16,450 --> 00:02:20,890
consisting of eight binary zeros can be manipulated.
20
00:02:20,890 --> 00:02:28,990
Now when we subnet think of submitting kind of like stealing butts we're going to steal butts from the
21
00:02:28,990 --> 00:02:30,310
host portion.
22
00:02:30,310 --> 00:02:37,560
We need to work out how many bits are required for the number of subnets that we need in this example
23
00:02:37,570 --> 00:02:39,840
we need four subnets.
24
00:02:39,840 --> 00:02:43,990
Now when it comes to subletting there are two formulas that you need to know.
25
00:02:44,070 --> 00:02:48,680
Two to the power of n and two to the power of n minus two.
26
00:02:48,780 --> 00:02:57,590
This formula is used when we asked for subnets which is what we've been asked in this question.
27
00:02:57,690 --> 00:03:02,140
This formula we need to use when we asked for a certain number of hosts.
28
00:03:02,220 --> 00:03:10,980
So if we were asked to subnet this subnet 1 9 2 1 6 8 1 0 select 24 and create as many subnets as possible
29
00:03:11,400 --> 00:03:18,210
each having 4 hosts we would use two to the power of n where n is the number of bits that are required
30
00:03:18,600 --> 00:03:20,020
minus two.
31
00:03:20,040 --> 00:03:26,490
So if we needed to get 4 hosts we would actually need two to the power of three minus two which would
32
00:03:26,490 --> 00:03:31,500
be to to power of three which is eight minus two which means that we would be able to have six hosts
33
00:03:31,500 --> 00:03:33,440
per subnet.
34
00:03:33,510 --> 00:03:39,920
We need to subtract two because of broadcast and network address but we don't need that.
35
00:03:40,080 --> 00:03:46,590
When asked for networks two to the power of two equals four which is what we need for the number of
36
00:03:46,590 --> 00:03:49,060
subnets that we've been asked to create.
37
00:03:49,080 --> 00:03:54,020
This is the number of bits that we stealing or using for the subnet portion.
38
00:03:54,060 --> 00:03:59,780
This is the number of bits that we would keep for the host portion.
39
00:03:59,810 --> 00:04:06,470
Now we're not using that formula so I can basically scratch that from our example.
40
00:04:06,560 --> 00:04:10,930
So basically remove that to we are not using that formula.
41
00:04:11,060 --> 00:04:14,780
In this example this is the formula that we need.
42
00:04:14,780 --> 00:04:21,590
And once again that's because we've been off to four subnets we haven't been asked for hosts.
43
00:04:21,860 --> 00:04:28,310
Now two to the power of one equals t that doesn't give us enough subnets due to the power of two gives
44
00:04:28,310 --> 00:04:35,540
us four subnet two to the power of three gives us eight subnets two to the power of four would give
45
00:04:35,540 --> 00:04:41,960
us sixteen subnets we don't need that many we only need four subnets.
46
00:04:42,230 --> 00:04:50,300
So all we need to do is use two bits which means we can steal two bits from the host portion for our
47
00:04:50,300 --> 00:04:51,470
subnet portion.
48
00:04:52,220 --> 00:05:03,560
So the host portion is now only six bits in length the subnet portion is now two bits in length.
49
00:05:03,560 --> 00:05:04,790
So write it like that.
50
00:05:04,850 --> 00:05:11,570
Once again there's obviously no spaces here in binary but that hopefully just makes it easier to read.
51
00:05:11,690 --> 00:05:20,740
So we're going to steal two bits from the host portion and allocate to that to the subnet portion.
52
00:05:20,770 --> 00:05:23,880
So how many bits are part of the network and subnet.
53
00:05:24,100 --> 00:05:28,240
We've got our 8 bits from our original example.
54
00:05:28,240 --> 00:05:33,470
An additional eight but from our original example plus eight bits.
55
00:05:33,580 --> 00:05:38,040
So that's sixteen plus one plus one.
56
00:05:38,080 --> 00:05:48,010
So in other words this is now a slash twenty six subnet it's no longer slash 24 because we've stolen
57
00:05:48,040 --> 00:05:52,950
bits from the host portion for the network portion.
58
00:05:53,170 --> 00:05:58,570
So the first network that we have is 1 9 2 1 6 8 1 dot 0.
59
00:05:58,750 --> 00:06:03,530
Look at to these 8 2 binary bits to make it easier to read.
60
00:06:03,640 --> 00:06:11,230
Notice we've got eight binary bits I've just split them up with spaces here to make it easier to demonstrate
61
00:06:11,710 --> 00:06:14,150
which party's subnet in which parties host.
62
00:06:14,170 --> 00:06:21,670
But notice there are eight binary but say eight binary bits equates to zero in decimal.
63
00:06:21,670 --> 00:06:26,450
So the network is 1 9 2 1 6 8 wondered 0 slash 26.
64
00:06:26,500 --> 00:06:28,680
That's our first network.
65
00:06:28,810 --> 00:06:31,270
Now what's the second network.
66
00:06:31,270 --> 00:06:34,830
The second network is 1 and 2 1 6 8 1.
67
00:06:34,990 --> 00:06:41,350
Dot and what we do now is we just go through the different binary options.
68
00:06:41,350 --> 00:06:44,440
This is 0 0 this is 0 1.
69
00:06:44,500 --> 00:06:49,030
This one would be 1 0 and this would be 1 1.
70
00:06:49,030 --> 00:06:52,930
So those are the different binary options that we have.
71
00:06:52,930 --> 00:07:01,200
So if we'll look at this network that second binary but to set to a one what does this equal to this
72
00:07:01,210 --> 00:07:04,920
equals to sixty four in a decimal.
73
00:07:04,960 --> 00:07:08,350
So the next network is 64.
74
00:07:08,350 --> 00:07:10,180
What is is this equal.
75
00:07:10,300 --> 00:07:12,710
It looks like this.
76
00:07:12,940 --> 00:07:15,650
Which equals 128.
77
00:07:15,650 --> 00:07:24,340
Now as soon as you've worked out this second subnet you can simply do addition by that number.
78
00:07:24,340 --> 00:07:32,620
So zero plus 64 64 plus 64 is 128 plus 64 is 192.
79
00:07:32,830 --> 00:07:39,760
But if you look at the binary it's 128 plus 64 which equals 192.
80
00:07:39,760 --> 00:07:46,460
So there are are four subnets that we've been asked to work out in this example.
81
00:07:46,540 --> 00:07:51,370
So we've got four subnets the first one is for side one the second one is for the link between right
82
00:07:51,370 --> 00:07:58,060
of one an Internet router third one is for side 2 fourth one is for the link between right at 2 and
83
00:07:58,090 --> 00:08:05,480
the Internet router so the first subnet would be 1 0 2 1 6 8 wondered slash 26.
84
00:08:05,800 --> 00:08:08,540
And I'll zoom in here to make it clearer.
85
00:08:08,920 --> 00:08:11,190
So that's our first subnet.
86
00:08:11,350 --> 00:08:21,810
Per our calculations second subnet is 1 9 2 1 6 8 1 64 slash 26.
87
00:08:21,840 --> 00:08:27,870
Third one is 1 9 2 1 6 8 1 128 slash 26.
88
00:08:27,870 --> 00:08:38,320
And the last one is 1 9 2 1 6 8 1 192 flash 26 so those subnets are these subnets that we worked out
89
00:08:39,540 --> 00:08:46,700
so we need to now configure the network with this information in the first step we need to work out
90
00:08:46,700 --> 00:08:53,760
to the subnets but now we need to configure the route as per the instructions so as an example the lost
91
00:08:53,790 --> 00:08:58,950
IP in the subnet should be configured on rather one second lost IP address should be configured on the
92
00:08:58,950 --> 00:09:07,390
switch third lost IP address should be configured on the DHB server per these instructions we also need
93
00:09:07,390 --> 00:09:15,150
to configure a DHB pool on the DHB server so I'm going to start with the subject first and get that
94
00:09:15,160 --> 00:09:18,040
working and then I'll move to the other subnets.
10068
Can't find what you're looking for?
Get subtitles in any language from opensubtitles.com, and translate them here.