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So let's make this quick exercise together, guys, because previously we know that the previous exercise
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when we had to write down a recursive function that gets an integer and returns one, if the sum of
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all the digits in the received number is even otherwise, return zero if it's odd.
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And basically we are going simply to modify it a little bit.
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So return one.
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If the sum of all digits in the received number is odd or otherwise return one, which means in the
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case that this sum is even OK.
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So very minor a change, very minor change.
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In this case, it's going to be zero.
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In this case it's going to be one.
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In this example.
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I just want to like to give it briefly for those of you who is who are interested, maybe some of you
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got the idea and you don't have to watch these video to her to the fullest or basically not at all.
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So.
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I'm just going to modify it a little bit to give you this code like crystal clear.
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OK, so if anything, less than 10 and basically that's the stopping condition.
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And if that's the case, we know that it can be divided by two without the remainder.
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OK, so this is an even number, right?
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So that means even number.
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And for an even number, we are going to return.
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What are we going to return?
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We are going to return one.
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OK.
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So in.
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Yeah, what if it's an even number we're going to return, we are going to return here zero, so OK,
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otherwise return zero.
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In case that's an even number.
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Awesome.
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So if that's an even number, return zero.
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And if that's an odd number, that's basically all the number we are going through a third one and the
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result so far is going to be calculated on the similar manner.
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OK, we are going to ask if An can be divided, basically the rightmost digit, if it's an even digit
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and the result so far is one, then in this case what we will have to return.
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What do you think?
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If the result so far equals to one, then it means that the result so far is order.
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Right.
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And if the results so far resolved and this number is even then even plus odd is basically odd.
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So that's why we have to return one.
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And if the result so far was equal to zero, in this case it was even right.
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And if it was even then, the result so far is even and we also know that the given value, the rightmost
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element of the rightmost digit is also even then in this case even plus even will equal to even.
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And that will mean that the return should be once again, zero.
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OK, so here it's going to also stay the same.
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OK.
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The only fact that change is here is not the code itself, but rather just this understanding.
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So if results of equals to one, then it means that the result so far was odd.
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OK, otherwise it was even.
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So that's basically just the way you look at the results so far and you don't have to change also these
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returns.
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So this exhibition or a demonstration, quick explanation is clear to you guys.
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And of course, take your time, try to solve it on your own and we will see each other again on in
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or.
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Yeah.
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In the next video until next time.
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My name is Lisas Alphatech.
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I'll see you then.
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